LEDs are blue, with a fwV of 4.2V and 40mA... EDIT: I've came to a formula, in the kitchen, while eating, lol... It' s for transistor amplification... x is for transistor use (0.6V, as previously discussed) E = ( ( C * B ) / x ) - x... That means if you have 10V going tough the transistor, using 2V, having 0.6V drain, you have this: E = ( ( 10V * 2V ) / 0.6V ) - 0.6V so E = ~32.73V Is that right?
I' ve been looking up on current voltages for superbright and standard LED' s together, and they' re all ~2V by 20-25mA... so then I' ll change my resistor to that... 'cept for Q2, everything looks okay, now? http://www.howlingwolfcompany.com/temp/Fancontroller2.gif
No, for transistor amplification you need to look for something called the gain of the transistor, either denoted by the greek character beta, or hfe. This is basically the ratio of Ice to Ibe. Diagram is looking better though!
Ehhhhhhh... Can you give a clear formula? As in how to actually calculate it without going all fuzzy up and down the characters... And thanks about the diagram, if that was referring to the circuit... ^-^
it isnt realy something that you want to calculate, but rather something that a data sheet is good for: (for example) if you realy want to figure it out, your looking at something like: which is want SteveyG said... but i would learn ohm's law before you get into semiconductor physics
More math: Current Gain = Ic / Ib (that is what you explained) Ic = Current Gain * Ib Ib = Ic / Current Gain Ue = Uc - Ub Hope that fits... now, I' m puzzled on what happens to the amps and the watts... Maybe anyone got a formula... after that, i' ve got all I need to get a figure of how the transistor works...
the rest is right, but this: what are you trying to do? i still dont understand in that formula, Ic and Ib are both in Amps. Current gain is in neither Amps, nor watts, it is a term that only pertains to the ratio of input to output. it serves no other function in any other electronics equation. its only purpose is to quantify the maximum amplification power of a transistor, so that you don’t have to do the math in you head while staring at a datasheet. remember, its not too important because its maximum gain, not absolute gain. 99% of the time we are only concerned with the current capacity (sorry for not being explicit before, capacity not draw) of a transistor, and the base current is irrelevant. in the 1% of the time that we have a device that cant source enough base current, we simply add a second transistor to handle the base of the bigger transistor. this is called a darling array. if i am missing your point entiarly, please explain it diffrently
All those formulas are the same thing except for the bottom one. Not sure where you worked that one out from, but the voltages totally depend upon your configuration and transistor type. What about the amps and the watts? The current is what you've just worked out in those equations. edit: Thanks for explaining the rest theshadow27, saved me some time!
tell you what... i think you are still thinking like ^^.... read http://www.williamson-labs.com/480_xtor.htm from the top to the bottom, click on all the pictures a few times, and dont post agein till you understand it
I am very ^-^ because I keep making progress, even with error... one lears from his mistakes... Ue = Uc - Ub, calculates the outlet voltage, since the transistor switch is standard 0.6V in every example of mine, and therefor draws 0.6V out of the Uc... I need the formula for Ie... I got Ic, Ib and If... but not Ie... And thanks for that tutorial... I' ll read it all... ^-^ got myself a whiteboard now for all my notes, saves paper for the actual important things... yay for me... And my money came trough, so from tomorrow on, I can do practical tests... woohoo!! Transistor blowups, here I come... hahahaha just kidding, though I don' t doubt it' d happen...
*-* whoah... beats me, *hand-over head sign* woosh... First off, this may sound really dumb, but I hate reading on a PC, unless it' s a little amount of text, or searching for specific parts of text... Secondly, I have no clue what that' s all about... all those images, all those applications... Is the transistor THAT variated? I thought it would be just a switch/amp- or voltincreaser... Help, lol... *panics* (tired + tech ed != good idea)
It's really best to try to understand all of that stuff on the page. That's only the basics. That is a pretty good tutorial for beginners, theshadow27. Well done on finding that for KDNenakh
can call me Kash, that' s easier... KDNenakh is my full name, shortened the first two names... I really appreciate the finding, but I' ll have to read it once I' m not that tired anymore, which would be tomorrow, most likely...
lol, that looks nice... (sarcasm) Hope they don' t splinter all over the place... I have a carpetfloor... not too nice to work on...
I' m being very unlucky here... the images are interpreted as images, by my brain... not as values or such... Wish they added more text to them... (on the images, not longer text on the page, that' s too much already)
--- QUOTE --- The results should resemble the figure: the diode signal starts up unimpeded until it reaches ~ 0. 6 volts peak (1.2 volts P - P), at which point the voltage at the "base" appears to stop increasing, even though the signal generator is still increasing in amplitude. No matter how much the voltage applied from the generator increases (within reason), the "base" voltage appears to not increase. However, the current into that junction (two anodes) increases linearly: I = [E - 0.6]/R --- this starts logical and then fades into the nothing of language difference
I' m becoming more and more frustrated that I don' t speak English as first, base language... I' ll try find something in Dutch, and just HOPE that it' s the correct (you guys don' t understand that for sure, so it' ll be little of use to have you check it)
