Just want to know how large of a resister (or potentometer) to use to take 3.3V down to 2-8-2.9V. Thanks
If you use a potential divider then u want your bottom resistor (R2) to be about 7 times greater than your top resistor (R1). So you could use values like: R1=13k R2=91k this should give you an output of 2.89V. So you could using a 100k potentiometer the you want it the ratio of 1:7 which would give you the same output. Not sure if this is what you wanted but meh its 3:30 in the morning. Raging
If you have a load that draws current the resistor network won't work. A few Schottky diodes, foward biased may do a better job. Your problem is that you don't have enough voltage drop to put a simple regulator, but then you may already know that. Could you regulate it down from 5V?
well there's going to be basically no current use. In essence, i'm just looking to tap my motherboards 3.3V line to boost DDR volage, as was done on an NF7 ages ago. thing is, i dont think my ram would appreciate 3.3v, and i dont need that much. So what your saying is that all i need is a 93 ohm (round to 100) coming from 3.3 in the line to the ddr point?
Found a solution . Rigged me up a 10K pot, and turned it down. Bottom end: 2.96V - A drop of .34V. Not quite good enough. I s'pose i'll just have to get a 20K pot - theoretically should offer a drop of .68V, letting me push voltages as low as 2.62 if needed. Does anybody have any of those little blue pots i can buy?
