Electronics Loudspeakers

Discussion in 'Modding' started by Tiberius, 8 Sep 2004.

  1. Tiberius

    Tiberius What's a Dremel?

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    Problem : We conect 2 loudspeakers serial/parallel .

    Loudspeaker1 : P=x1 W , Z=y1 Ohms
    Loudspeaker2 : P=x2 W , Z=y2 Ohms

    ----------------------------------------

    Pserial=?;Zserial=?
    Pparallel=?;Zparallel=?
     
    Tiberius, 8 Sep 2004
    #1
  2. Cougar4

    Cougar4 What's a Dremel?

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    I'm not sure what you are asking here. If you connect speakers in series you just add the resistance of each speaker to get the total resistance of them tied together (ie. 8 ohms plus 8 ohms equals 16 ohms).

    If you place them in parallel, and the resistance is the same for each speaker, then you can just divide the resistance of the speaker by the amount of the speakers you use (ie. two 8 ohm speakers in parallel would be 8/2=4 ohms). If the resistance is not the the same then the equation is a little more complicated. It is not a good idea to use speakers of different impedences tied directly together since they will have diffent SPL levels.
     
    Cougar4, 8 Sep 2004
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  3. Tiberius

    Tiberius What's a Dremel?

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    How about the power ? What happens when you connect 2 speakers in series/parallel ?
     
    Tiberius, 9 Sep 2004
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  4. SteveyG

    SteveyG Electromodder

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    Power dissipated effectively doubles in parallel, and halves in series. If this is for actual use in a system, beware your amp may not be able to handle the low impedances.
     
    SteveyG, 9 Sep 2004
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  5. ConKbot of Doom

    ConKbot of Doom Minimodder

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    for impedance in parallel Zp = 1/((1/Z1)+(1/Z2)+.....(1/Zn))
    in series Zs=Z1+Z2+Z3....+Zn

    Im not sure how to calculate the power through each speaker though.
     
    ConKbot of Doom, 9 Sep 2004
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  6. corvette

    corvette What's a Dremel?

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    mate here it is in really simple terms


    2x 100watt Drivers @ 8Ohms in parrelel = 200Watts @ 4 Ohm


    2x 100Watt Drivers @ 8Ohm in series = 100watts @ 16 Ohm

    ( i think the second 1 is right )

    Each speaker should get equal power rights in theory other wise a Dual 4 Ohm voice coil sub for a car wired in parralel wouldnt work
     
    corvette, 13 Sep 2004
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  7. cpemma

    cpemma Ecky thump

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    SteveyG had it right. Just use the power law, W=V2/R

    The amp has a fixed output voltage at a given volume setting (set by the input signal voltage level & amp gain) so power doubles for 2 speakers in parallel and halves for 2 speakers in series. :thumb:
     
    cpemma, 13 Sep 2004
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  8. awakeallnight

    awakeallnight What's a Dremel?

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    Dual voice coil series+parallel

    One of my favorite solutions to achieving proper load on an amp with two speakers is to get two dual voice coil speakers. Connect the two voice coils on each speaker in series and then connect the resulting pairs in parallel to the amp. See dumpy artwork below:

    |--- +Vc1- -- +Vc2- ---|
    | \ / |
    (+ amp terminal)-------| speaker 1 |--------- (- amp terminal)
    | |
    | |
    | |
    | speaker 2 |
    | / \ |
    |--- +Vc1- -- +Vc2- ---|

    This will keep your amp running at a normal load, thus (at least normally speaking) increasing its overall life. The power would be divided by 2; half of the power going to each speaker.
     
    awakeallnight, 18 Sep 2004
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