Development PHP Help

I am halfway through making a MySQL class to interface with the db and be shiny and stuff but i am unable to understand an error i get.

PHP:

class mysqlClass{
    var $queryres;        #used to return the results of a query
    var $result;        #used to store the results of a query
    var $numrows;       #used to store the number of rows
    var $connection;    #used as a connection reference 
    
    function mysqlClass($details){
        $this->user['host'] = $details['host'];
        $this->user['user'] = $details['user'];
        $this->user['pass'] = $details['pass'];
        $this->user['db'] =   $details['db'];        

        $this->connection = @mysql_connect($this->user['host'], $this->user['user'], $this->user['pass']) || die("Connect error"); #connect to mySQL
        $this->selectDatabase($this->user['db'], $this->connection);    #select appropriate db
        
    }

    function selectDatabase($database){
        @mysql_select_db($database) || die ("Db select error");
    }

    function closeConnection(){
                mysql_close($this->connection);
    }

         //more functions here.
            
        
}


If i use that to make an object like $conn = new mysqlClass($array); it connects, and selects the database fine. If i then call $conn->closeConnection(); i get the error Warning: mysql_close(): supplied argument is not a valid MySQL-Link resource, and cannot understand why.

Any help would be usefull
Col

 

lol, thought this looked a bit familiar.

Have already replied on Xaprief.


PS - Someone else that uses #comments - woo. Don't seem to see many of them.