Ok i got 4 RBG LEDs and they came with 6 stubs (2 common cathodes, 2 blue anodes, one red anode, and one green anode). I need some responses for the following reasons: a) is this the configuration for the LEDs b) where would i wire the stubs to, i heard cathodes go to + and anodes go to - but where are these, a diagram could be great i need to include the following: 4x RBG LEDs 4x rocker switches (one for red, one for blue, one for green, and one for on/off) 3x resistors (one for each color) 12v power line (of course) The LEDs that control the colors have three stubs, one for ground, one for power, and one for the thing you're controlling, the power LED has two stubs and i dont need any advice on that. i need answers quick pleeeeeeeeeeez
Are you sure it is 2 common cathode 2 blue anodes... and not just 1 cathode and 1 anode for each? I would just take a 5v line, and 250 ohm resistor (whatever you have that is close) and start probing at the LED connecting the + to each pin and the - to each pin and see what lights up for each. With 5v and the 250 you are providing 2.5v@10 mA so you don't run the risk of blowing anything unless it is low-current also. You'll have to figure out which pin goes to what. If you are lucky though there is 3 seperate dies that you can see, and you can see the pins go to each of them.
Not here, I hope. Cathode is the pointed end of the diode symbol and goes towards ground or - to conduct. Unless it's a zener diode. +V---Res-----anode->|-cathode-------0V It could be like http://www.rapidelectronics.co.uk/r...&CTL_CAT_CODE=&STK_PROD_CODE=M61380&XPAGENO=5, a red & blue with common cathode, and a green & blue with a different common cathode.
you need resistors of course anodes are + cathodes are - green and red are 220 ohms at 12v hook both blue leads together with a 100ohm resistor at 12v you need 3 resistors for each LED... no matter how many LEDs you have.
one question: there needs to be a branch off the power line that goes to a resistor then goes to ground? why?
i dont know what your talking about... the thing right under the power switch is the power LED... i dont see any resistors going to ground, that would be stupid
ok k but what about the LED pin config, whick pins are which, here is a diagram of the underside of the LED:
http://www.globalspec.com/FeaturedProducts/Detail?ExhibitID=7779&fromSupplier=1 http://www.mouser.com/index.cfm?handler=data.getPcodes&pcode=Kingbright+LED+RGB&pcodenumber=60419 Took google 0.4 seconds.
ya, lol, i googled and that still doesnt answer my question, im not using a board, im gonna solder the wires to the leads. im just guessing but i think the red and green stars are the leads for the red and green anodes, i just dont know whick are which, i think the blue stars are the two blue anode leads, and i think the yellow stars are the cathodes. this is just a guess
It's all in the datasheet that cpemma linked you to. How does that not answer your question?? http://www.us.kingbright.com/data/spec/LF59EMBGMBW.pdf
i have the square not round one, the sheet labels the leads 1-6 but never defines which are which. yes i know i am a retard, can some one just ell me which are which if they know, hooking up and trying out the combos takes to long if i can just have someone tell me.
if you have the kingbright led... then my diagrams wrong... you should have said what modle the LED was.... according to the datasheet: http://www.kingbright-led.com/data/spec/AAF5060PBESEEVG.pdf as for the resistors... blue ~ 30ma @ 3.7v hyper orange ~ 50ma @ 2.0v green ~ 30ma @ 4.0v go to the metkumods resistor calculator: http://www.metku.net/index.html?sect=view&n=1&path=mods/ledcalc/index_eng to figure out the resistors some people right
I know im an idiot/n00b/whatever u wanna call me but pleeeeese bear with me. i no tells what pins are what but being the non-electrician that i am i cant decifer it. thanx for all the BTW shadow
wow ... do you not even try ... this is from the web site i asked you to go to: http://www.metku.net/index.html?sect=view&n=1&path=mods/ledcalc/index_eng there are 3 diodes inside one case... thus the 3 arrows. any more questions
ok ok i tried, just not too hard. so i need the negative leads to go to ground and the positive leads to go to the switches?
